3-b. A stone is thrown vertically upward with a velocity of 40 m/s. What is (a) maximum height attained and (b) the time taken to reach its maximum height?
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Very simple !!
maximum height attend given by formula =>
h = u²/ 2g
40× 40/ 2× 10
=> 80 m
time taken to reach maximum height given by formula :-
u / g
=> 40/10
4 sec .
kindly look formula carefully it help you lot to calculate these type of problem in short cut .
hope it help you !!
thanks
maximum height attend given by formula =>
h = u²/ 2g
40× 40/ 2× 10
=> 80 m
time taken to reach maximum height given by formula :-
u / g
=> 40/10
4 sec .
kindly look formula carefully it help you lot to calculate these type of problem in short cut .
hope it help you !!
thanks
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