Question

3 bells ring at an interval of 4,7 and 14 minutes. All three bell rang at 6 am,

when th
e three balls will the ring together next?

​

Answer 1

Answer:

6:28 am

Step-by-step explanation:

LCM of 4 ,7 ,14 is 28

so they will ring in a interval of 28 minutes.

Answer 2

Answer:

The three bells ring together again at 6:28 am.

Step-by-step explanation:

Given 3 bells ring at an interval of 4, 7 and 14 minutes.

And all the three bells rang at 6 am.

Given the numbers 4, 7 and 14

From the prime factorization method, the least common multiple (LCM) of the numbers is the product of prime factors raised to their respective highest power.

Writing the given numbers as the product of their prime factors,

4 = $2\times 2=\underline2^{2}$

7  $=\underline7^{1}$

and 14 = $2\times2\times 7=\underline2^{2}\times \underline7^{1}$

Thus, the LCM of the given numbers is $2^{2}\times 7^{1}=4\times 7=28$

Hence, after 28 minutes, all the three bells ring together again.

Therefore, all the three bells ring together again at 6:28 am.