Question

3 boxes have some average weight. when one box which weight 89 kg is replaced by another box, the average weight increased by 5 kg. how much the new box weight​

Answer 1

Z=104 kg

Step-by-step explanation:

Let the weight of each box be x,y,z

$\therefore$third box weight is given = 89

$\frac{x+y+89}{3}=x\\x+y+89=3x\\y+89=2x\\y=2x-89$

when one box is replaced by another box the average weight increased by 5

so,

$\frac{x+y+z}{3}=x+5\\\frac{x+2x-89+z}{3}=x+5\\3x-89+2=3x15\\z=15+89\\z=104$