Question

3 boys and 3 girls are to sit in a row. Howmany ways can this be done if(i) there are no restrictions(ii) there is a girl at each end(iii) boys and girls are at alternate places(iv) all boys sit together​

Answer 1

Step-by-step explanation:

36 is the answer of the questions

Answer 2

Answer:

i)At the first where there is no restriction they can sit randomly = n! =6!=720.

ii)then girls at end

They took 1 out of 3 and then 1 out of remained 2

3____2 this will be the chances

Then we have to pack the blank

We have 4 students and can sit randomly =4!

The total chances=3×4!×2=144.

iii)when alternative position they will sit like /_/_/_ or _/_/_/ here boy=/ and girl=_

Then the solution is 3!×3!×2=72

Here 3! Is for arranging boys and that is same for girls.

iv) when boys are together they can be taken as a single unit but can be arranged 3! on their own unit

total no. of arrangements = 4!×3!=144