Question

3.
Calculate the bulk modulus of elasticity of brass given that for brass Y = 10 x10'0N/m?
and n =3.7 x100 N/m².​

Answer 1

Answer:

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Explanation:

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Answer 2

The bulk modulus of elasticity of brass is 1.12×$10^{11}$ N/m².

Given:

Young's modulus of brass (Y) = 10×$10^{10}$ N/m

Modulus of rigidity of brass ($\eta$) = 3.7 × $10^{10}$ N/m²

To Find:

The Bulk modulus of elasticity of brass.

Solution:

Let us consider K as the bulk modulus of elasticity of brass.

We know the relation between Y, $\eta$ and K is as follows:

$\frac{9}{Y}= \frac{1}{K} +\frac{3}{\eta}$

By putting the values we get,

$\frac{9}{10*10^{10} } - \frac{3}{3.7*10^{10} } = \frac{1}{K}$

⇒K= 1.12×$10^{11}$

Hence, the bulk modulus of elasticity of brass is 1.12×$10^{11}$ N/m².

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