Question

3. Calculate the molar mass of the following compounds?
a. H2So4. b. Na2CO3 (Atomic mass: C=12, H=1, O=16, S=32 and Na=23)
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Answer 1

Answer:

#H2So4 :-

=>Molecular mass of H2SO4 =

olecular mass of H2SO4 =2×molar mass of Hydrogen + molar mass of Sulphur + 4×molar mass of Oxygen

(2×1)+(32)+(4×16)2+32+6498

=>so molecular mass of H2SO4 or sulphuric acid is 98.

#Na2CO3 :-

=> Molar mass=

(2*22.98976928 g/mol Na)+ (1*12.0107 g/mol C)+(3*15.999 g/mol O)

=>105.987 g/mol Na2CO3

Answer 2

Given: The compounds are $H_2SO_4$ and $Na_2CO_3$

To find: We have to find the molar mass.

Solution:

$H_2SO_4$

The atomic mass of H is 1 and the atomic mass of Sulfur is 32. The atomic mass of Oxygen is 16.

The molar mass of the compound is as follows-

$2 \times 1 + 32 + 4 \times 16 \\ = 2 + 32 + 64 \\ = 98$

The molar mass of sulfuric acid is 98grams.

$Na_2CO_3$

The atomic mass of Na is 23 and the atomic mass of C is 12. The atomic mass of Oxygen is 16.

The molar mass of the compound is as follows-

$2 \times 23 + 12 + 3 \times 16 \\ 46 + 12 + 48 \\ = 106$

The molar mass of sodium carbonate is 106grams.