3. Calculate the pressure exerted by cubical block placed over the
surface.
50 kg, side length 5 cm.
m
5.00
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pressure, p =?
m = 50 kg
f = mass x acceleration
f = 50 x acceleration due to gravity
= 50 kg x 9.8 m/s2
= 490 n side of cube is given = 5 cm
= 5 x 10-2 m
area of the face of cube on which the force is applied is a = (5 x 10-2)2m²
= 25 x 10-4 m²
pressure = force/ area
= 490 n/ 25 x 10-4 m2
= 196000 n/m2
= 196000 pa
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