3 capacitors are in parallel and one of them is in series with parallel combination. Resultant capacity is 3.75uf. What is the capacity of each capacitor
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Answered by
1
Answer:
each capacitor will be 5.625 μF
Explanation:
see it in pic
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Answered by
0
Answer:
Consider the capacitance as C
In parallel combination ,
C1=C+C+C=3C
In series Combination ,
1/Cf= 1/3.75 = 1/3C+1/C
=> C = 5 micro Farad.
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