Question

3 chairs and 2 tables costs Rs 700 and 5 chairs and 3 tables cost rs 1100. the cost of one chair is

Answer 1

Let the cost of a chair be x.

Let the cost of a table be y.

Given that 3 chairs and 2 tables cost 700 rupees 

 3x + 2y = 700  ------ (1)

Given that 5 chairs and 3 tables cost 1100 rupees.

5x + 3y = 1100  ------ (2)

On solving (1)*3 and (2)*2, we get

10x + 6y = 2200

9x + 6y =  2100

----------------------

x = 100.

Substitute x = 100 in (1), we get

3x + 2y = 700

3(100) + 2y = 700

300 + 2y = 700

2y = 700 - 300

2y = 400

y = 400/2

y = 200.

Therefore the cost of 2 chairs = 2 * 100

                                                   = 200 rupees.

Therefore the cost of 2 tables = 2 * 200

                                                   = 400 rupees.

Verification:

3x + 2y = 700

3(100) + 2(200) = 700

300 + 400 = 700

700 = 700.

5x + 3y = 1100

5(100) + 3(200) = 1100

500 + 600 = 1100

1100 = 1100.

Hope this helps!

Answer 2

Let the cost of a chair be x.
Let the cost of a table be y.
Given that 3 chairs and 2 tables cost 700 rupees 
3x + 2y = 700  ------ (1)
Given that 5 chairs and 3 tables cost 1100 rupees.
5x + 3y = 1100  ------ (2)
On solving (1)*3 and (2)*2, we get
10x + 6y = 2200
9x + 6y =  2100
x = 100.
Substitute x = 100 in (1), we get
3x + 2y = 700
3(100) + 2y = 700
300 + 2y = 700
2y = 700 - 300
2y = 400
y = 400/2
y = 200.
Therefore the cost of 2chairs is 2×100= 200 rupess
= 400 rupees.