The diagonal of a Rhombus are 18cm and24cm. find its area and perimeter
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its formula is half*d1*d2
answer is 216 cm^2 is area
answer is 216 cm^2 is area
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As the diagonals of rhombus bisects each other by 90°
By Pythagoras theorem,
9²+12²=side
169=side²
13=side
Perimeter of rhombus =13*4=52cm
Area of rhombus =18*24/2 =18*12 =216cm²
By Pythagoras theorem,
9²+12²=side
169=side²
13=side
Perimeter of rhombus =13*4=52cm
Area of rhombus =18*24/2 =18*12 =216cm²
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