Question

3 coins are tossed simultaneously.find the probability of getting 1. Two head 2. at least two head
3. All head

Answer 1

Answer:

3/8, 1/2, 1/8 respectively

Step-by-step explanation:

3 coins are tossed simultaneously. The sample space will be:

n(S) = 2ⁿ = 2³ = 8

S: [HHH, HHT, HTH, THH, HTT, THT, TTH, TTT]

1. Event A: Two Heads

A: [HHT, HTH, THH]

n(A) = 3

p(A) = n(A) / n(S)

       = 3 / 8

2. Event B: Atleast Two Heads

B: [HHT, HTH, THH, HHH]

n(B) = 4

p(B) = n(B) / n(S)

       = 4 / 8

       = 1 / 2

3. Event C: All Heads

C: [HHH]

n(C) = 1

p(C) = n(C) / n(S)

       = 1 / 8