Question

3. Compute the zeroes of the polynomial 4x2 – 4x – 8. Also, establish a relationship between the zeroes and coefficients.

pls give the steps and i will mark it as brainliest

Answer 1

Step-by-step explanation:

p(x)=4x²-4x-8=0

=>4x²+4x-8x-8=0

=>4x(x+1)-8(x+1)=0

=>4(x-2)(x+1)=0

=>x=-1,2

Answer 2

Answer:-

Factorise the equation 4x2 – 4x – 8 = 0

4x2 – 4x – 8 = 0

4x2 – 2x – 2x + 1 = 0

2x(2x – 1) – 1(2x -1) = 0

(2x – 1) (2x – 1) = 0

So, the roots of 4x2 – 4x – 8 are (½ and ½)

Relation between the sum of zeroes and coefficients:

½ + ½ = 1 = -4/-4 i.e. (- coefficient of x/ coefficient of x2)

Relation between the product of zeroes and coefficients:

½ × ½ = ¼ i.e (constant/coefficient of x2)