Question

rationalise√6/√2+√3​

Answer 1

Answer:

Multiply numerator and denominator by (√3+√2)

[√6(√3+√2)]/(√3-√2)(√3+√2)

=> (√18+√12)/(√3)²-(√2)²

( a+b)(a-b) => a²-b²

=> (√18+√12)/3-2

=> √18+√12

OR

√6 / ( √3-√2 )

= √6 ( √3 + √2 ) / ( √3-√2 )( √3 + √2 )

= ( √6 * √3 ) + ( √6 * √2 ) / ( √3 )² - ( √2 )²

= √18 + √12 / ( 3 -2 )

= 3√2 +2√3 ( ANSWER )

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Answer 2

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