Math, asked by rollingstone8, 1 year ago

3 consecutive numbers of a series are in A.P with d=2, smallest number?

Answers

Answered by asp2051980
0

jgummmmmmmcjukghbhjn;l/okl'[;

[]lplpjo

Answered by Anonymous
0

Generally an A.P progresses as

a, (a+d), (a+2d), (a+3d), (a+4d)... and so on.

Thus, the smallest number of any A.P is always the number with no 'common difference'(d) part.

That is 'a' is the smallest number.

In the question an A.P of 3 consecutive numbers with common difference 2 is mentioned. Value of 'a' is not given.

Thus, some examples:

i) When a=1

1, (1+2), (1+4) = 1, 3, 5

1 is the smallest.

ii) When a=0

0, (0+2), (0+4) = 0, 2, 4

0 is the smallest.

ii) When a=-1

-1, (-1+2), (-1+4) = -1, 1, 3

-1 is the smallest.


Similar questions