Question

3 consecutive positive even integers whose sum is 216

Answer 1

Answer:

the numbers are 71,72 and 73.

hope this helps.....

Answer 2

Let the 1st Number be x.

then, the 2nd & 3rd number will be (x + 2) & (x + 4) respectively.

A/Q :-

$x + x + 2 + x + 4 = 216 \\ 3x + 6 \\ 3x = 210 \\ x = 70$

Hence, Required Number will be 70, 72, & 74.