Question

3 cos 80° cosec 10° + 2 sin 59° sec 31° make me understand......​

Answer 1

Step-by-step explanation:

3 cos 80°. cosec 10° + 2 sin 59° sec 31°

= 3cos (90° – 10°) cosec 10° + 2sin (90° - 31°) sec 31°

=3 sin 10° cosec 10° + 2 cos 31°,

sec 31° .[sin (90° – teta) = cos teta, cos (90° - teta) = sin teta]

=3×1 +2 x 1

.....[: sin teta. Cosec teta = 1, cos teta sec teta = 1]

= 5

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Answer 2

Answer:

5

Step-by-step explanation:

3 cos (90 - 10) x cosec 10 + 2 sin 59 x sec (90 - 59)     [cos (90 - A) = sin A]

3 sin 10 x cosec 10 + 2 sin 59 x cosec 59                              (sin x cosec = 1)

3 + 2 = 5