Question

3 cosec²60° - 2 cot²30°+ sec²45°=0​

Answer 1

Answer:

proved

Step-by-step explanation:

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Answer 2

Answer:

$\huge\orange{\overbrace{\red{\underbrace{\color{pink}{{\red\:{Question}}}}}}}$

$Q.\:3\:cosec²60°–\:2\:cot²30°,+\:sec²45°\:=\:0$

$\huge\orange{\overbrace{\red{\underbrace{\color{pink}{{\red\:{Solution}}}}}}}$

$✠\:cosec \:60° = \frac{2}{ \sqrt{3} }$

$✠\:cot \: 30° = \sqrt{3}$

$✠\:sec \: 45° = \sqrt{2}$

$\red{A/Q,}$

$➯3\:cosec²60°–\:2\:cot²30°,+\:sec²45°\:=\:0$

$➯ 3 \times ( \frac{2}{ \sqrt{3} } ) {}^{2} - 2 \times ( \sqrt{3} ){}^{2} + ( \sqrt{2}) {}^{2} = 0$

$➯3 \times \frac{4}{3} - 2 \times 3 + 2 = 0$

$➯ \:4 - 6 + 2 = 0$

$➯ - 2 + 2 = 0$

$➯ \:0 = 0$

$\underline\red{✮Hence,\:Proved!}$

$\huge\orange{Thank\:You.!}$