3 cubes each of 5cm edge are joined end to end.find the
surface area of the resulting cuboid
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Length of the cuboid, l = 2 × each side of the cube = 2 × 5 cm = 10 cm
Breadth of the cuboid, b = each side of the cube = 5 cm
Height of the cuboid, h = each side of the cube = 5 cm
Surface area of the cuboid
= 2 (lb + bh + hl)
= 2 (10 cm × 5 cm + 5 cm × 5 cm + 5 cm × 10cm)
= 2 (50 cm2 + 25cm2 + 50 cm2)
= 2 × 125 cm2.
= 250 cm2.
Thus, the surface area of the resulting cuboid is 250 cm2.
Breadth of the cuboid, b = each side of the cube = 5 cm
Height of the cuboid, h = each side of the cube = 5 cm
Surface area of the cuboid
= 2 (lb + bh + hl)
= 2 (10 cm × 5 cm + 5 cm × 5 cm + 5 cm × 10cm)
= 2 (50 cm2 + 25cm2 + 50 cm2)
= 2 × 125 cm2.
= 250 cm2.
Thus, the surface area of the resulting cuboid is 250 cm2.
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