Question

3 cubes each of edge 1m, 6m, 8m, respectively are melted and made into one one single cube,find the surface area of the new cube.​

Answer 1

Step-by-step explanation:

V1 + V2 + V3 = Vnew

1³ + 6³ + 8³ = side³

side³ = 729

so, side = 9m

surface area of cube = 6l²

= 6 (9)²

= 6 x 81

= 486 m²

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Answer 2

Answer:

${a1}^{3} + {a2}^{3} + {a3}^{3} = {a}^{3}$

By substituting values:

1³ + 6³ + 8³ = a³

1 + 216 + 512 = a³

729 = a³

$\sqrt[3]{729} = a$

a = 9m

Surface area of cube = 6a²

= 6 × 81

= 486 m²

Hope it helps

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