3 cubes of sides are in the ratio of 3:4:5 are melted to form a new cube of diagonal 15√3.Find the measure of sides of initial cubes
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Ratio of the sides: 3:4:5
Let the edges of the 3 cubes be:
3x, 4x and 5x
Vol of 3 small cubes = Vol of big cube
(3x)³ + (4x)³ + (5x)³ = 216x³
Diagonal = ∛216x³
= 12√3
√a²+a²+a² = 12√3
a√3 = 12√3
a = 12
x = 12/6
x = 2
Sides of the initial cubes are:
3x = 6cm
4x = 8cm
5x = 10cm
suprit1729:
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