3 dice are thrown simultaneously, find the probability of getting a sum 15.
Answers
Answered by
6
Three dice are thrown simultaneously.
The combinations that result in a sum of 15 are:
(5, 5, 5), (3, 6, 6), (4, 5, 6)
Total number of permutations for the above combinations:
1 + 3!/2! + 3! = 10
Desirable outcomes = 10
Total number of outcomes if 3 dice are thrown: 6 × 6 × 6 = 216.
Probability = 10/216 = 5/108.
The combinations that result in a sum of 15 are:
(5, 5, 5), (3, 6, 6), (4, 5, 6)
Total number of permutations for the above combinations:
1 + 3!/2! + 3! = 10
Desirable outcomes = 10
Total number of outcomes if 3 dice are thrown: 6 × 6 × 6 = 216.
Probability = 10/216 = 5/108.
kvnmurty:
:-)
Nice answer
sir
Answered by
1
ANSWER
............
THE COMBINATION IN THE SUM OF THE 15.
IS
(5,5,5,).....(3,6,6,)===== (4,5,6)
1+3//2+3= 10
6*6*6 =216
216/10 108
............
THE COMBINATION IN THE SUM OF THE 15.
IS
(5,5,5,).....(3,6,6,)===== (4,5,6)
1+3//2+3= 10
6*6*6 =216
216/10 108
Similar questions