3 different coins are tossed together find the probability of getting exactly 2 heads and 2 tales
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Answered by
1
Since three coins are tossed therefore sample space of the experiment is
S={HHH ,TTT,HHT,HTH,THH,TTH,THT,HTT}
A=Exactly two heads =p(A)=3/8
B=exactly two tails =P(B)=3/8
(The answer is according to the question )
S={HHH ,TTT,HHT,HTH,THH,TTH,THT,HTT}
A=Exactly two heads =p(A)=3/8
B=exactly two tails =P(B)=3/8
(The answer is according to the question )
Answered by
4
Total no. of possible outcomes = 8
HHH, HTH , HHT ,HTT, TTT, THT, TTH, THH
(1) probability of getting exactly 2 heads=
There are 3 outcomes where exactly 2 heads appear= HTH, HHT, THH
No. of favourable outcomes =3
PROBABILITY=3/8
(2) Probability of getting exactly 2 tales=
There are 3 outcomes where exactly 2 tales appear= HTT, THT, TTH
No. of favourable outcomes =3
PROBABILITY=3/8
MARK AS BRAINLIEST PLEASE
HHH, HTH , HHT ,HTT, TTT, THT, TTH, THH
(1) probability of getting exactly 2 heads=
There are 3 outcomes where exactly 2 heads appear= HTH, HHT, THH
No. of favourable outcomes =3
PROBABILITY=3/8
(2) Probability of getting exactly 2 tales=
There are 3 outcomes where exactly 2 tales appear= HTT, THT, TTH
No. of favourable outcomes =3
PROBABILITY=3/8
MARK AS BRAINLIEST PLEASE
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