Question

[3-Dimension X,Y,Z]Find the Shortest Line segment(Defined by 2 Points A,B) Between a Triangle(Defined by 3 Points Q,W,E) And a Line Segment(Defined By 2 Points R,T)
Point A Should be Within the Triangle(Q, W, E).
Point B Should be Within the Line Segment(R, T).

Answer 1

Answer:

If sin A = 1/3

$sina = oppsite/adjcent = 1/3$

$pythagoras \: formula = ac {}^{2} = ab { }^{2} + bc {}^{2} \\ 3 {}^{2} = ab {}^{2} + 1 {}^{2} \\ 9 = ab {}^{2} + 1 \\ 9 - 1 = ab {}^{2} \\ ab { = \sqrt{8} }^{2} \\ = 4$

Answer 2

Step-by-step explanation:

Given that, Area of rhombus =84 m

2

Perimeter of rhombus =40 m

We know that, Perimeter of rhombus =4 × side

∴ Side of rhombus =

4

Perimeter

=

4

40

=10

So, Side of rhombus =10 m

Since we know that rhombus is a parallelogram.

∴ Area of parallelogram = base × altitude

⇒84=10 × altitude

⇒ Altitude =

10

84

=8.4

So, Altitude of rhombus =8.4 m