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Two water taps together can fill a tank in 9 hours. The tap of larger diameror takes 10
hours less than the smaller one to fill the tank separately. Find the time in which each tap
can separately fill the tank.
Answers
Answered by
2
Answer:
now let the time taken by the larger tap be x and smaller one be y , so
Now the part of tank filled by the larger tap in 1 hr. =1/x and similarly the part of tank filled by the smaller tap in 1 hr. be 1/y
now as according to the question the tap of the larger diameter takes 10 hrs. less than the smaller one to fill the tank ,
Step-by-step explanation:
Now 1/x+1/y=1.....(1)
1/x-10/y=0..........(2)
so , y=11 and x=1.1 means approx. 1 hrs.
hope it helps !!!✌✌✌
Answered by
0
Answer:
y=11, x= 11
Step-by-step explanation:
approx 1 he's.
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