Math, asked by saralalakkakula, 8 months ago

3. Each Question carries 8 Marks
4x 8 = 32
Calculate the area of a quadrilateral ABCD when length of the diagonal
AC= 10 cm. and the lengths of perpendiculars from B and D onto AC
be 5 cm and 6 cm respectively.
(OR)
Standing at 5 m apart from a vertical pole of height 3 m. Sailin served​

Answers

Answered by mythilimannava
2

Answer:

654

Step-by-step explanation:

Answered by joelpaulabraham
1

Answer:

55 cm²

Step-by-step explanation:

Let ABCD be the Quadrilateral and AC = 10cm and perpendicular from B to AC = 5cm and perpendicular from D to AC = 6cm

Now ABC and ADC are triangles

Therefore area of Quadrilateral ABCD = ar(ABC) + ar(ADC)

Area of triangle=(1/2)×base×altitude(or perpendicular height)

ar(ABC) = (1/2)×10×5 = 25 cm²

ar(ADC) = (1/2)×10×6= 30 cm²

therefore ar(ABCD) = 25 + 30 = 55cm²

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