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Factorise 125x² 64y^3
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125x³-64y³
=(5x)³-(4y)³
now,
5x³-4y³ [identity:a³-b³=(a-b)[a²+ab+b²]
(5x-4y)[(5x)²+(4y)²+5x×4y]
(5x-4y)[25x²+16y²+20xy]
hope this answer will help you.
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