Question

3. Factorise :
(i) x8-y8​

Answer 1

$\huge\underline\mathtt\red{Your\:Answer}$

= $\mathtt{x^8-y^8}$

= (x⁴-y⁴)(x⁴+y⁴)

= {(x²)² – (y²)²} (x⁴ + y⁴)

= (x² – y²) (x² + y²) (x⁴ + y⁴)

= (x – y) (x + y) (x² + y²) (x⁴ + y⁴)

= (x – y) (x + y) (x² + y²) {(x²)² + (y²)² + 2x²y² – 2x²y²}

= (x – y) (x + y) (x² + y²) {(x² + y²)² – √2xy)²}

= (x – y) (x + y) (x² + y²) (x² + y² – √2xy) (x² + y⁴ + √2xy)

Thank You!!