In right angle triangle two circles are placed which touch each other . If smaller circle has radius 2cm find thevradius of bigger circle.
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Step-by-step explanation:
First draw figure as instructed
- a. triangleABC where angle B=90
- draw both circle like given in the Q
- centre of bigger circle =O'
- of smaller circle=O
- join O'to O and to C
- construct triangleCEO' angle C = 90 and it is point of contact of bigger circle and lie on hypotenuse of triangleABC
- NOW CONSTRUCT point of contact of smaller corcle=P
- make triangle CPO
- Po ll EO' in triangle CEO'
- SOLUTION
Let radius of bigger circle isEO'=rcm
angle PCO=30
IN TRIANGLE POC
sin30=PO/CO=1/2
CO=4cm
now CR=6cm henceCO'= 6+r cm
Now in triangle CEO'
sin30=1/2=EO/CO'
r/6+r=1/2(EO=r ,CO= 6+r)
2r=6+r
r=6cm
hence radius of bigger circle is 6cm
salute to sudhakar sir
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