Question

(3.) Factorize:
25a2 – 4b2 + 28bc - 49c2
pls answer this class 8th question​

Answer 1

Answer:

${25a}^{2} - {4b}^{2} + 28bc - 49 {c}^{2} \\ {25a}^{2} -( {4b}^{2} - 28bc + 49b {}^{2} ) \\ 25 {a}^{2} - (2b - 7c) {}^{2} \\ (5a) {}^{2} -(2b - 7c) {}^{2} \\ (5a - 2b -7c)(5a + 2b -7c)$

Hope it Helps you✌

Answer 2

Answer:

25a^2 - 4b^2 + 28bc - 49c^2

(5a)^2 - (4b^2 - 28bc + 49c^2)

(5a) ^2 - (2b - 7c) ^2