Math, asked by tanujamondal838, 9 months ago

3. Find each of the following products:
(i) (-4)x(-5)(-8)X(-10)
Nii)(-60)*(-10)*(-5)*(-1)
(v) (-3)*(-3)*(-3)* ... 6 times
(ii) (-1)×(-1)^(-1)... 200 times​

Answers

Answered by Anvesh311
12

Answer:

(1) (-4)×(-5)×(-8)×(-10)

= +20×-8×-10

=+20×80

=1600.

(2)(-60)×(-10×(-5)×(-1)

=+600×-5×-1

=+600×+5

=+3000

(3) -3×-3×-3×-3×-3×-3

=(+9)×(+9)×(+9)

= (+729)

(4) Here the (-1) is even times....

So,(-1)×(-1)........200 times is. +1.

Hope this hepls you....

Mark me as brainliest please...

Answered by sy4928162
0

Answer:

+1

Step-by-step explanation:

here,(-1)×(-1)...200times

so, 200 is a even number

if we do (-1)×(-1) we will get 1

and 1x1=1

so,our answer will be +1

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