Question

3)find HCF of given below: k,2k,3k,4k,5k,6k

Answer 1

Step-by-step explanation:

The hcf of k,2k,3k,4k,5k,6k=k

Because k is common factor of all and it's the only common factor other than 1

So HCF is K

Answer 2

Answer:

Given number are K, 2K, 3K, 4K & 5K

where K is any positive integer.

Now K=K

2K=2×K

3K=3×K

4K=2×2×K

5K=5×K

In all these numbers highest common factor is K.

Hence HCF of all given number is K.