Question

3. Find the area of a rhombus whose one side
is equal to 10 cm and the length of one of
the diagonals is 12 cm.​

Answer 1

Answer:

There ar different ways of doing it, one method is as follows…..

Rhombus ABCD, AB= 10cm , So BC = 10cm , as all sides of rhombus are equal.

Diagonal AC = 12cm

So, area( tri ABC) by Heron's formula

= √{ s(s-a)(s-b)(s-c) } , s is semi perimeter & a,b,c are sides of the triangle

= s = 32/2 = 16

Area = √{16 *(16–10)(16–10)(16–12)

=> area = √(16*6*6*4)

=> area = √(2²*2²*2²*3²*2²)

=> area = 2*2*2*3*2 = 48 cm²

=> area (Rhombus ABCD) = 48*2 = 96 cm²