Question

3. Find the area of trapezium whose parallel sides are of length 16 dm and 22 dm and
whose height is 12 dm.(with calculation)​

Answer 1

Answer:

Step-by-step explanation:

Given: Base of trapezium (b

1

​

)=16 dm

Base of trapezium (b

2

​

)=22 dm

Height of trapezium (h)=12 dm

Now, Area of trapezium =

2

1

​

×(b

1

​

+b

2

​

)×h

=

2

1

​

×(16+22)×12

=

2

1

​

×38×12

=228 dm

2

=

100

228

​

m

2

[∵1 dm

2

=

100

1

​

m

2

]

=2.28 m

2

Answer 2

Answer:

228 dm²

Step-by-step explanation:

area of trapezium is : 1/2(sum of parallel sides)(height)

Given: length of parallel sided is 16 dm and 22 dm.

height is 12 dm.

Implying all the the given values:

1/2(16+22)(12)

2 gets cancelled with 12 and becomes 6.

now 16+22 that is 38 is multiplied with 6 as per the formula.

the answer is 228 dm²