Question

(3. Find the distance of the point (3, -5) from the
3x-4y-26=0.
​

Answer 1

Perpendicular distance of a point(x1,y1) from a line(Ax+By+C=0) is given by (Ax1+By1+C)/(A2+B2)1/2.

So distance of point(1,3) from given line(x+4y+1=0) is:14/(17)1/2.