Question

3. Find the following products:
(i) (4a - 3b)(5a + 6b)
ii) (a + 2)(2a - 3)(3a + 2)​

Answer 1

$\sf{Answer}$

Step by step explanation:-

1) (4a-3b)(5a+6b) =

We can find the product directly

(4a-3b)(5a+6b) = 4a(5a+6b) -3b(5a+6b)

= 20a² +24ab -15ab -18b²

= 20a² + 9ab -18b²

So, the product of (4a-3b)(5a+6b) = 20a²+9ab-18b²

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2) (a+2)(2a-3)(3a+2)

First find product of (a+2)(2a-3)

So,product of (a+2)(2a-3) = a(2a-3)+2(2a-3)

= 2a²-3a+4a-6

= 2a² +a -6

Now find product of 2a²+a-6 &3a+2

(2a²+a-6)(3a+2)

2a²+a-6(3a) + 2a²+a-6(2)

6a³+3a²-18a +4a²+2a-12

6a³+7a² -16a -12

So the product of (a + 2)(2a - 3)(3a + 2) is 6a³+7a² -16a -12

hope my answer helps to u:)