Question

3. Find the LCM and HCF of the following integers by applying the prime factorisation
method.
(1) 12,15 and 21 (2) 17,23 and 29 (3) 8,9 and 25​

Answer 1

Answer:

12 = 2×2×3

15 = 5×3

21 = 7×3

there for LCM OF 12,15, & 21=3

Step-by-step explanation:

17=17×1

23=23×1

29=29×1

LCM=1

8=2×2×2

9=3×3

25=5×5

LCM=1

Answer 2

:

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Using prime factorisation method:

(i) 12, 15 and 21

Factor of 12=2×2×3

Factor of 15=3×5

Factor of 21=3×7

HCF (12,15,21)=3

LCM (12,15,21)=2×2×3×5×7=420

(ii) 17, 23 and 29

Factor of 17=1×17

Factor of 23=1×23

Factor of 29=1×29

HCF (17,23,29)=1

LCM (17,23,29)=1×17×23×29=11,339

(iii) 8, 9 and 25

Factor of 8=2×2×2×1

Factor of 9=3×3×1

Factor of 25=5×5×1

HCF (8,9,25)=1

LCM (8,9,25)=2×2×2×3×3×5×5=1,800