Question

3. Find the measure of all the angles of a parallelogram
ABCD, if d measures 60​

Answer 1

Answer :

Given:ABCD is a parallelogram and D=60°

D=B=60°(opposite angles are equal)

A+D=180°(adjacent angles are supplementary)

A+60°=180°

A=180°-60°

A=120°

A=C=120°(opposite angles are equal)

Hope it is helpful.

Mark me as brainlist.

Follow me.

Answer 2

Answer:

Question:-

Find the measure of all the angles of a parallelogram ABCD, if ∠D is 60°.

Given:-

∠D of parallelogram ABCD is 60°.

To Find:-

All the angles of a parallelogram ABCD.

Solution:-

We know that,

Opposite angles of a parallelogram are equal.

Therefore,

∠D = ∠B = 60°.

And,

Let ∠A = ∠B = X.

Since,

• ∠A + ∠B + ∠C + ∠D = 360°.
• X + X + 60° + 60° = 360°.
• 2X + 120° = 360°.
• 2X = (360 - 120)°.
• 2X = 240°.
• ${\boxed {X = 120°.}}$

Therefore,

• ∠A = 60°.
• ∠B = 60°.
• ∠C = 120°.
• ∠D = 120°.

Answer:-

In Parallelogram ABCD,

• ∠A = 60°.
• ∠B = 60°.
• ∠C = 120°.
• ∠D = 120°.

More to know:-

1. Opposite sides are congruent (AB = DC).
2. Opposite angles are congruent (D = B).
3. Consecutive angles are supplementary (A + D = 180°).
4. If one angle is right, then all angles are right.
5. The diagonals of a parallelogram bisect each other.
6. Each diagonal of a parallelogram separates it into two congruent triangles.
7. Area = b × h Square units

Where “b” is the base and “h” is the height of the parallelogram.