Question

3 ② find the no of moles 1 liter of 0.01 m of H*2so*4 in presant
sollution ?​

Answer 1

Answer:

The number of moles of 1 L of 0.01 M of H*2so*4 in present solution is 0.01 moles.

Explanation:

volume of sulphuric acid is 1 L

molarity of sulphuric acid is 0.01 M

Therefore, molarity can be given as follows:

Molarity = number of moles/ Volume in Litres

On substituting all the values it gets-

0.01 M = moles/1 L

Hence,

moles = 0.01 * 1

= 0.01 moles