Question

3) Find the resultant resistance in the
following arrangement of resistances.





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Answer 1

Explanation:

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Answer 2

let R1=5 om

R2 = 15om

R3 = 2.25 om

5om and 15 om are in parallel order

so let resistance = R4

$\frac{1}{r4} = \frac{1}{r1} + \frac{1}{r2} \\ \frac{1}{r4} = \frac{1}{5} + \frac{1}{15} \\ \: \: \: \: \: \: \: = \frac{3 + 1}{15} \\ \: \: \: \: \: \: \: = \frac{4}{15} \\ \frac{1}{r4} = \frac{4}{15} \\ r4 = \frac{15}{4}$

resistance R3 and R4 in line order

so let total resistance = R5

$r5 = r3 + r4 \\ \: \: \: \: \: = 2.25 + \frac{15}{4} \\ \: \: \: \: \: = \frac{5 + 15}{4} \\ \: \: \: \: \: = \frac{20}{4} \\ r5 = 5$

so total resistance in circuit = 5 om

answer