Question

maths question - Ramu drink all the water from his water bottle in several sips.In every sip,he drinks double the amount of water he drank in the previous sip.If he drinks 115th of the water in the bottle in the first sip,in how many sips will he empty the bottle​

Answer 1

Answer:

7 sips

Step-by-step explanation:

Let the initial amount of water in the bottle be x

then

Sip 1;

Ramu drinks 115th of the water ie.

$\frac{1}{115}*x=\frac{1}{115}x$

The remaining amount is

$x-0.008695652x = 0.991304348x$

Sip 2;

Ramu drinks twice the amount in sip 1 which is

$0.008695652x*2=0.017391304x$

the remaining amount is

$0.991304348x-0.017391304x=0.973913043x$

Sip 3;

Ramu drinks twice the amount in sip 2 which is

[tex]0.017391304 x*2=0.034782609 x[/tex]

the remaining amount is

[tex]0.973913043 x-0.034782609x=0.939130435 x[/tex]

Sip 4;

Ramu drinks twice the amount in sip 3 which is

$0.034782609  x*2=0.069565217  x$

the remaining amount is

$0.939130435  x-0.069565217  x=0.869565217  x$

Sip 5;

Ramu drinks twice the amount in sip 4 which is

[tex]0.069565217   x*2=0.139130435 x[/tex]

the remaining amount is

[tex]0.869565217 x-0.139130435  x=0.730434783 x[/tex]

Sip 6;

Ramu drinks twice the amount in sip 5 which is

$0.139130435    x*2=0.27826087  x$

the remaining amount is

$0.730434783  x-0.27826087  x=0.452173913  x$

Sip 7;

He can drink  [tex]0.27826087      x*2=0.556521739 x[/tex]

which is more than the remaining amount.

therefore Ramu empties the bottle  in 7 sips