3. Find the smallest number which when divided by 12, 10 and 20 leaves no reminder
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Answered by
0
Step-by-step explanation:
60 if it can be divided by 12 OR 20
60 / 12 = 5
60 / 20 = 3
get the prime factors of both
20 = 5 * 2 * 2
12 = 2 * 2 * 3
Then merge the factors keeping what’s in common between the 2 and adding the others.
5 * 2 * 2 * 3 = 60 (2 * 2 is in common so we just include that once.)
If however, you say that the number has to be divisible by both 12 AND 20, then you just combine all the factors, or you just simply multiply the 2 numbers together.
So, 5 * 2 * 2 * 2 * 2 * 3 = 240 or 12 * 20 = 240.
240 / 12 = 20
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Answered by
1
Answer:
60 is the answer
60/12 = 5
60/ 10 = 6
60/ 20 = 3
Step-by-step explanation:
we can find the number by finding the LCM of 12, 20 and 10
which is equal to 60
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