Question

3. Find the sum of 25 terms of the AP 2,2V2, 3√2, 4v2.....​

Answer 1

Step-by-step explanation:

n=25 a=2 d=t3-t2=

$3 \sqrt{2} - 2 \sqrt{2} = \sqrt{2}$

$sn = \frac{n}{2} (2a + (n - 1)d) \\ \: \: \: \: \: \: \: = \frac{25}{2} (2(2) + 24 \sqrt{2}) \\ = \frac{25}{2} (4 + 24 \sqrt{2} ) \\ = \frac{25}{2} \times 2(2 + 12 \sqrt{2} ) \\ = 25 \times 2 + 12 \sqrt{2} \\ = 50 + 12 \sqrt{2}$