Question

3. Find the total distance covered by Rohit if he takes 5 rounds of a rectangular park of length
75 cm and breadth 25 cm
Find the ratio of 90 cm to 1.5 m.
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Answer 1

Question

Find the total distance covered by Rohit -------- breadth 25 cm.

SOLUTION

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 75 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 25 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Length(l) of the rectangular park = 75cm.

Breadth(b) of the rectangular park = 25cm.

Distance covered by Rohit if he takes one round around the park = Perimeter of the park.

Perimeter of a rectangle = 2(l+b)

⇒ Perimeter of the rectangular park = 2(75 + 25)

⇒ Perimeter of the rectangular park = 2 × 100

⇒ Perimeter of the rectangular park = 200cm = 2m.

Distance covered by Rohit if he takes 1 round around the park = 200 cm.

∴ Distance covered by Rohit if he takes 5 round around the park = 5 × 200

$\red\bigstar$  Distance covered by Rohit if he takes 5 round around the park  = 1000cm or 10m.

Question

Find the ratio of 90 cm to 1.5 m.

SOLUTION

Let us convert 1.5m to cm

$\boxed{\sf 1\:Meter(m) = 100 \:Centimeter(cm)}$

⇒ 1.5m = 1.5 × 100cm

⇒ 1.5m = 150cm

$\sf Ratio = \dfrac{90}{150}$

$\implies \sf Ratio = \dfrac{9}{15} = \dfrac{3}{5}$

$\red\bigstar \sf Ratio \: of \; 90\: cm\: to\: 1.5 m = \dfrac{3}{5}$

​

Answer 2

Answer:

1. 1000cm.
2. 3:5

Step-by-step explanation:

Question(s) -

1. Find the total distance covered by Rohit if he takes 5 rounds of a rectangular park of length75 cm and breadth 25 cm.
2. Find the ratio of 90 cm to 1.5 m.

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Solution (1)-

$\rightarrow$ Length =75 cm.

$\rightarrow$ Breadth = 25 cm.

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➠ㅤDistance travelled in one round =$\bold\red{Perimeter}$

$\color{orange}\boxed{\colorbox{saffron}{Perimeter-2(length+breadth) }}$

$2(75 + 25) \\ \\ = 2 \times 100 \\ \\ = 200 \: cm$

So, perimeter/the distance travelled in one round= 200 cm.

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➠ㅤDistance travelled in 5 rounds =$\bold\green{5×perimeter}$

=5×200

= 1000 cm.

So, distance travelled in 5 rounds is 1000 cm.

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Solution(2)-

Given numbers -

$\rightarrow$ 90 cm.

$\rightarrow$ 1.5 m = 150 cm.

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= 90:150

= $\cancel{90}{:}\cancel{150}$

= $\cancel{30}{:}\cancel{50}$

= $\cancel{3}{:}\cancel{5}$

= $\bold\blue{90}{:}\bold\blue{150}$