Question

3. Find the value of 'k' for which the system of equation 2x + 3y = 5 and 4x + ky = 10 has infinite number of
solution.​

Answer 1

Answer:

Hii friend,

2X+KY = 1..........(1)

3X -5Y = 7...........(2)

These equations are in the Form of A1X+B1Y +C1 = 0 And A2X+B2Y+C2 = 0

Where,

A1 = 2 , B1 = K , C1 = -1

A2 = 3 , B2= -5 and C2 = -7

For unique solution we must have,

A1/A2 is not equal to B1/B2

2/3 not = K/-5

-5 × 2 = 3 × K

3K = -10

K = -10/3

Answer 2

Answer:

6

Step-by-step explanation:

For infinite number of solutions,a1/a2=b1/b/2=c1/c2

2/4=3/k=5/10

2/4=3/k

k=6

3/k=5/10

k=6