Question

3. Find the value of k, when the distance between the points (3.2k) and (4.1) is
10 units.
-find value of k


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Answer 1

Answer:

the distance between two points=√(x2-x1)²+(y2-y1)²

10=√(4-3)²+(1-2k)²

10=√1²+(1-2k)²

squaring on both sides,

10²=1+(1-2k)²

100-1=(1)²+(2k)²-2(1)(2k)

99-1=4k²-5k

4k²-5k-98=0

if you solve this equation you will get k value.

Good night