3. Find the value of the polynomial p(x)=2x²-x²+3x+1 at x=-1..
Answers
Answered by
0
Answer:
1
Step-by-step explanation:
2(-1)²-(-1)²+3(-1)+1=1
hope it helps
Answered by
0
r(x2) = (x2)2 - 5x2
Similarly: p(x+1) = 2(x+1)2 - 3(x+1) + 1
so r(x2) - p(x+1) = (x2)2 - 5x2 - (2(x+1)2 - 3(x+1) + 1)
= x4 - 5x2 - ((2x2 + 2x + 1) - 3x - 3 + 1)
= x4 - 5x2 - 2x2 - 2x - 1 + 3x + 3 - 1
= x4 - 7x2 + x
= x ( x3 - 7x + 1)
Similar questions