Question

3. Find the value of the unknowns. b) AB X5 CAB . I need
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Answer 1

Answer:

AB×5=CAB,

(10A+B)×5=100C+10A+B,

50A+5B=100C+10A+B

40A+4B=100C

B=5, then 38A=100C not possible.

B=0, then 40A=100C

Only possible values are A=5,C=2

Therefore A+B+C=7

Thus, the answer is 7.

Step-by-step explanation:

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