Question

3. Find the value of x for which (8x + 4), (6x – 2) and (2x + 7) are in AP.

Standard:- 10

Answer 1

6x-2-8x-4=2x+7-6x+2
-2x-6=-4x+9
4x-2x=9+6
2x=15
x=15/2

Answer 2

Heya !!!



AP = ( 8X + 4 ) , ( 6X - 2) and ( 2X + 7)


Here,


First term (A) = 8X+4


Second term (A2) = 6X-2


And,


Third term (A3) = 2X+7

Common Difference (D) = A2-A1

=> ( 6X -2) - ( 8X + 4)


=> 6X-2 - 8X - 4


=> - 2X - 6



Also,


Common Difference (D) = A3-A2



=> ( 2X + 7) - ( 6X - 2)


=> 2X + 7 - 6X + 2


=> -4X + 9


As we know that,

Common Difference of an AP is always equal.


So,



A2-A1 = A3-A2



-2X - 6 = -4X + 9



-2X + 4X = 9+6



2X = 15



X = 15/2.



★ HOPE IT WILL HELP YOU ★