Question

3. Find the zeros of the polynomial x² – 3x – m(m + 3).​

Answer 1

ANSWER...

• YOU CAN USE QUADRATIC FORMULA FOR THIS QUESTION

I WILL PROVIDE YOU TWO DIFFERENT METHOD FOR THIS QUESTION FIRST BY FACTORISATION AND OTHER BY QUADRATIC FORMULA...

1. FACTORISATION METHOD

${x}^{2} - 3x - m(m + 3) = 0 \\ \\ {x}^{2} + (m)x - (m + 3)x - m(m + 3) = 0 \\ \\ x(x + m) - (m + 3)(x + m) = 0 \\ \\ (x + m)(x - (m + 3)) = 0 \\ \\ first \: value \: of \: x = - m \\ \\ second \: value \: of \: x = m + 3$

2. QUADRATIC FORMULA

$a = 1 \\ b = - 3 \\ c = - m(m + 3) \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x = \frac{ - ( - 3) + \sqrt{ { - 3}^{2} - 4(1)( - m(m + 3))} }{2(1)} \\ \\ x = \frac{3 + \sqrt{ 9 + 4 {m}^{2} + 12m } }{2} \\ x = \frac{3 + \sqrt{ {(2m + 3)}^{2} } }{2} \\ solution \: of \: x \\ \\ x = \frac{3 - (2m + 3)}{2} = \frac{ - 2m}{2} = - m \\ \\ solution \: of \: x \: \frac{3 + 2m + 3}{2} = \frac{2m + 6}{2} ={m + 3}$

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Answer 2

Refers to attachment!!

hope IT HELPs!!