Math, asked by vandana448585, 3 months ago

3. Find two numbers such that the sum of thrice the first number and twice the second number is 102. Also five
times the first number exceeds thrice the second number by 18. Find the numbers,



answer is 18,24
please I want processs​

Answers

Answered by chandanapukalyani
13

Step-by-step explanation:

first number be x

second number be y

sum of thrice the first number and twice the second number is 102

I.e., 3x+2y=102 eqn1

five times the first number exceeds thrice the second number by 18

I.e., 5x-3y=18 eqn2

solving eqn1 and eqn2

eqn1*3 gives 9x+6y=306

eqn2*2 gives 10x-6y=36

19x=336

x=~18

subs in eqn2

90-3y=18

3y=90-18

y=24

Answered by syed2020ashaels
3

The given question is the sum of thrice the first number and twice the second number is 102. Also five

times the first number exceeds thrice the second number by 18.

we have to find the two numbers.

let the first and second numbers be x and y respectively.

The first condition is the sum of thrice the first number and twice the second number is 102.

The expression is

3x + 2y = 102

The second condition is five times the first number exceeds thrice the second number by 18.

The expression is

5x - 3y = 18

let the equation be (1) and (2).

we can solve this problem by an elimination method.

equation 1 * 3 we get 9x+6y=306

eauation 2*2 we get. 10x-6y=36.

Adding these two equations we get, 19x = 336.

Therefore the value of x will be 18.

substitute x =18 in 2 nd equation

5x - 3y = 18 \\ 5(18) - 3y = 18 \\ 90 - 3y = 18 \\ 90 - 18 = 3y \\ 72 = 3y \\  \frac{72}{3}  = y \\ 24

The value of x and y will be 18 and 24

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